5x^*45+45=0+45,5x2+0=0+45,

Solution for 5x^*45+45=0+45,5x2+0=0+45, equation:

5x^*45+45=0+45.5x^2+0=0+45.

We move all terms to the left:

5x^*45+45-(0+45.5x^2+0)=0

Wy multiply elements

-(0+45.5x^2+0)+225x+45=0

We get rid of parentheses

-45.5x^2+225x-0-0+45=0

We add all the numbers together, and all the variables

-45.5x^2+225x+45=0

a = -45.5; b = 225; c = +45;
Δ = b2-4ac
Δ = 2252-4·(-45.5)·45
Δ = 58815
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{58815}=\sqrt{9*6535}=\sqrt{9}*\sqrt{6535}=3\sqrt{6535}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(225)-3\sqrt{6535}}{2*-45.5}=\frac{-225-3\sqrt{6535}}{-91}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(225)+3\sqrt{6535}}{2*-45.5}=\frac{-225+3\sqrt{6535}}{-91}
$